### Question:
Tuple3 extends Tuple2<T1, T2> implements Tuple { @Override public int hashCode() { return Objects.hash(super.hashCode(), item3); } Tuple3(T1 a, T2 b, T3 c); static Tuple3<T1, T2, T3> of(T1 a, T2 b, T3 c); T3 getItem3(); @Override Object nth(int index); @Override Tuple3<T, T2, T3> mapItem1(Function<T1, T> mapper); @Override Tuple3<T1, T, T3> mapItem2(Function<T2, T> mapper); Tuple3<T1, T2, T> mapItem3(Function<T3, T> mapper); @Override List<Object> asList(); @Override int size(); @Override int hashCode(); @Override boolean equals(Object o); @Override String toString();  }### Answer:
@Test public void testHashCode() { Tuple3<Integer, Integer, Integer> same = new Tuple3<>(1, 2, 3); Tuple3<Integer, Integer, Integer> different = new Tuple3<>(1, 2, 1); assertThat(someTuple.hashCode()) .isEqualTo(same.hashCode()) .isNotEqualTo(different.hashCode()); }