### Question:
Tuple6 extends Tuple5<T1, T2, T3, T4, T5> implements Tuple { @Override public int hashCode() { return Objects.hash(super.hashCode(), item6); } Tuple6(T1 a, T2 b, T3 c, T4 d, T5 e, T6 f); static Tuple6<T1, T2, T3, T4, T5, T6> of(T1 a, T2 b, T3 c, T4 d, T5 e, T6 f); T6 getItem6(); @Override Tuple6<T, T2, T3, T4, T5, T6> mapItem1(Function<T1, T> mapper); @Override Tuple6<T1, T, T3, T4, T5, T6> mapItem2(Function<T2, T> mapper); @Override Tuple6<T1, T2, T, T4, T5, T6> mapItem3(Function<T3, T> mapper); @Override Tuple6<T1, T2, T3, T, T5, T6> mapItem4(Function<T4, T> mapper); @Override Tuple6<T1, T2, T3, T4, T, T6> mapItem5(Function<T5, T> mapper); Tuple6<T1, T2, T3, T4, T5, T> mapItem6(Function<T6, T> mapper); @Override Object nth(int index); @Override List<Object> asList(); @Override int size(); @Override String toString(); @Override boolean equals(Object o); @Override int hashCode();  }### Answer:
@Test public void testHashCode() { Tuple6<Integer, Integer, Integer, Integer, Integer, Integer> same = Tuple6.of(1, 2, 3, 4, 5, 6); Tuple6<Integer, Integer, Integer, Integer, Integer, Integer> different = Tuple6.of(1, 2, 1, 4, 6, 10); assertThat(someTuple.hashCode()) .isEqualTo(same.hashCode()) .isNotEqualTo(different.hashCode()); }